3.1299 \(\int \frac{(1-2 x)^2}{(2+3 x)^3 (3+5 x)} \, dx\)

Optimal. Leaf size=39 \[ \frac{217}{9 (3 x+2)}+\frac{49}{18 (3 x+2)^2}-121 \log (3 x+2)+121 \log (5 x+3) \]

[Out]

49/(18*(2 + 3*x)^2) + 217/(9*(2 + 3*x)) - 121*Log[2 + 3*x] + 121*Log[3 + 5*x]

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Rubi [A]  time = 0.0181591, antiderivative size = 39, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 1, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.045, Rules used = {88} \[ \frac{217}{9 (3 x+2)}+\frac{49}{18 (3 x+2)^2}-121 \log (3 x+2)+121 \log (5 x+3) \]

Antiderivative was successfully verified.

[In]

Int[(1 - 2*x)^2/((2 + 3*x)^3*(3 + 5*x)),x]

[Out]

49/(18*(2 + 3*x)^2) + 217/(9*(2 + 3*x)) - 121*Log[2 + 3*x] + 121*Log[3 + 5*x]

Rule 88

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Int[ExpandI
ntegrand[(a + b*x)^m*(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, p}, x] && IntegersQ[m, n] &&
(IntegerQ[p] || (GtQ[m, 0] && GeQ[n, -1]))

Rubi steps

\begin{align*} \int \frac{(1-2 x)^2}{(2+3 x)^3 (3+5 x)} \, dx &=\int \left (-\frac{49}{3 (2+3 x)^3}-\frac{217}{3 (2+3 x)^2}-\frac{363}{2+3 x}+\frac{605}{3+5 x}\right ) \, dx\\ &=\frac{49}{18 (2+3 x)^2}+\frac{217}{9 (2+3 x)}-121 \log (2+3 x)+121 \log (3+5 x)\\ \end{align*}

Mathematica [A]  time = 0.0163725, size = 48, normalized size = 1.23 \[ \frac{1302 x-2178 (3 x+2)^2 \log (5 (3 x+2))+2178 (3 x+2)^2 \log (5 x+3)+917}{18 (3 x+2)^2} \]

Antiderivative was successfully verified.

[In]

Integrate[(1 - 2*x)^2/((2 + 3*x)^3*(3 + 5*x)),x]

[Out]

(917 + 1302*x - 2178*(2 + 3*x)^2*Log[5*(2 + 3*x)] + 2178*(2 + 3*x)^2*Log[3 + 5*x])/(18*(2 + 3*x)^2)

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Maple [A]  time = 0.006, size = 36, normalized size = 0.9 \begin{align*}{\frac{49}{18\, \left ( 2+3\,x \right ) ^{2}}}+{\frac{217}{18+27\,x}}-121\,\ln \left ( 2+3\,x \right ) +121\,\ln \left ( 3+5\,x \right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((1-2*x)^2/(2+3*x)^3/(3+5*x),x)

[Out]

49/18/(2+3*x)^2+217/9/(2+3*x)-121*ln(2+3*x)+121*ln(3+5*x)

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Maxima [A]  time = 1.01628, size = 49, normalized size = 1.26 \begin{align*} \frac{7 \,{\left (186 \, x + 131\right )}}{18 \,{\left (9 \, x^{2} + 12 \, x + 4\right )}} + 121 \, \log \left (5 \, x + 3\right ) - 121 \, \log \left (3 \, x + 2\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^2/(2+3*x)^3/(3+5*x),x, algorithm="maxima")

[Out]

7/18*(186*x + 131)/(9*x^2 + 12*x + 4) + 121*log(5*x + 3) - 121*log(3*x + 2)

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Fricas [A]  time = 1.53105, size = 159, normalized size = 4.08 \begin{align*} \frac{2178 \,{\left (9 \, x^{2} + 12 \, x + 4\right )} \log \left (5 \, x + 3\right ) - 2178 \,{\left (9 \, x^{2} + 12 \, x + 4\right )} \log \left (3 \, x + 2\right ) + 1302 \, x + 917}{18 \,{\left (9 \, x^{2} + 12 \, x + 4\right )}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^2/(2+3*x)^3/(3+5*x),x, algorithm="fricas")

[Out]

1/18*(2178*(9*x^2 + 12*x + 4)*log(5*x + 3) - 2178*(9*x^2 + 12*x + 4)*log(3*x + 2) + 1302*x + 917)/(9*x^2 + 12*
x + 4)

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Sympy [A]  time = 0.133958, size = 31, normalized size = 0.79 \begin{align*} \frac{1302 x + 917}{162 x^{2} + 216 x + 72} + 121 \log{\left (x + \frac{3}{5} \right )} - 121 \log{\left (x + \frac{2}{3} \right )} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)**2/(2+3*x)**3/(3+5*x),x)

[Out]

(1302*x + 917)/(162*x**2 + 216*x + 72) + 121*log(x + 3/5) - 121*log(x + 2/3)

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Giac [A]  time = 1.23697, size = 45, normalized size = 1.15 \begin{align*} \frac{7 \,{\left (186 \, x + 131\right )}}{18 \,{\left (3 \, x + 2\right )}^{2}} + 121 \, \log \left ({\left | 5 \, x + 3 \right |}\right ) - 121 \, \log \left ({\left | 3 \, x + 2 \right |}\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^2/(2+3*x)^3/(3+5*x),x, algorithm="giac")

[Out]

7/18*(186*x + 131)/(3*x + 2)^2 + 121*log(abs(5*x + 3)) - 121*log(abs(3*x + 2))